Jun 30, 2022 · L L — Length of the wire (one-way), measured in meters; and A A — Cross-sectional area of the wire, measured in square meters. After combining and rearranging these two equations, the cross-sectional area is given by the equation:** A = \frac {I \varrho 2 L} {V} A = V I ϱ2L**.

Calculates the maximum **wire** **length** of a single round **wire** of common conducting materials using the **formula** below. **Wire** **Length** = ( VD x 1000) / (LC x 2 x R) Where: VD = Voltage Drop LC = Load Current R = Resistance. The resistance is then matched to the corresponding **wire** gauge value as per the American **Wire** Gauge standard (AWG).. For a cable, resistance is calculated by the following **formula**: where, R is the resistance in ohms (Ω). ρ is the resistivity in ohms-meter (Ω×m) l is the **length** **of** the conductor in meter (m) s is the cross sectional area of the conductor in square meters (m 2) In the chart below you can see the specific resistance Ω · mm2 / m of the most. Estimate the **Length** **of** a **Wire**. You can use this calculator to estimate how much **wire** is left on a spool. Start by measuring the resistance of the **length** **of** **wire**. Use an ohmmeter to measure the resistance of the **wire**. If you use a 2-wire measurement the calculator assumes you have 0.2 ohms of lead resistance. If you make a four-**wire** measurement. Web. Web.

## gj

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## ul

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="3c88043c-a927-4e99-b071-cdda0e6d61ae" data-result="rendered">

**guy wire**

**length**that we are looking for. The "right triangle" is formed by the angle at the base of the tower or mast forming a 90 degree angle to the earth AND the guy point away from the installation. Here is the

**formula**: Said another way... C squared = A squared plus B squared.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="a676f327-eadc-4809-b40a-62a9783996dc" data-result="rendered">

**A = \frac {I \varrho 2 L} {V} A = V I ϱ2L**. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="c464f94b-4449-4e5e-aeab-b1fb780deb4f" data-result="rendered">

## rd

**Length**= (2*Force)/ (pi*Diameter

**of Wire***Stress in

**wire**due to fluid pressure) Go

**Length of**cylinder in terms

**of**initial tensile force in

**wire Length**= Force/ ( (pi/2)*Diameter

**of Wire***Initial winding stress) Go Thickness

**of**cylinder in terms

**of**initial compressive force in cylinder for

**length**'L'. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="c9fcc261-dde9-4af6-96a4-871ce9c843a7" data-result="rendered">

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="e9108589-8920-4ae9-9727-6b6c3f3959ac" data-result="rendered">

**Roll Length Calculator**; Contact Us. Corporate Headquarters (508) 885-8200 FAX (508) 885-8400. Troubleshooting & Support; Locations; Careers; Follow us. Sign up for .... " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="4197ad16-4537-40bb-a12d-931298900e68" data-result="rendered">

## jy

**Formula**used is, Cable size= (Fault current (in kA)*Fault clearing time)/K where, K-constant depending on the conductor and insulation used. K=90 (for Al cables), K=140 (for Cu cables) Step 2 is normally done for HT cables. For LT, if the circuit breaker used is ACB, then this step is done. For MCCB, this step is ignored.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="35fff56c-bbf1-4990-a77e-8ffa5f60080d" data-result="rendered">

**Length**= (2*Force)/ (pi*Diameter

**of Wire***Stress in

**wire**due to fluid pressure) Go

**Length of**cylinder in terms

**of**initial tensile force in

**wire Length**= Force/ ( (pi/2)*Diameter

**of Wire***Initial winding stress) Go Thickness

**of**cylinder in terms

**of**initial compressive force in cylinder for

**length**'L'. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="b88da2e9-fae2-4b6b-9d5b-47d3f8541001" data-result="rendered">

## qt

**Formula**used is, Cable size= (Fault current (in kA)*Fault clearing time)/K where, K-constant depending on the conductor and insulation used. K=90 (for Al cables), K=140 (for Cu cables) Step 2 is normally done for HT cables. For LT, if the circuit breaker used is ACB, then this step is done. For MCCB, this step is ignored.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="9ef17ea2-ef45-4ae3-bd5b-cf93789e8b08" data-result="rendered">

**guy wire**

**length**that we are looking for. The "right triangle" is formed by the angle at the base of the tower or mast forming a 90 degree angle to the earth AND the guy point away from the installation. Here is the

**formula**: Said another way... C squared = A squared plus B squared.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="73c9f638-a2d6-4fcd-8715-cbbd147d0bf4" data-result="rendered">

## rq

**Wire**Weight and

**Length**Calculations for the

**Wire**Division. For more information please contact us at 888-843-2350.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="d13eab01-5c9b-4dfd-97fa-17c82d4e5e68" data-result="rendered">

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="a6d1e317-2a68-412a-ac27-144ef69937ca" data-result="rendered">

**Length of wire formula**physics with detailed solutions. Exercise 1 : When applying a voltage of 12V to the ends of a coil

**of wire**, the current through it has a magnitude of 0.6A. Calculate the

**length**of the

**wire**used to wrap that

**wire**. Given that this type of conductor has a

**length**of 8m, the resistance is 4Ω.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="c4ef3b89-a313-4f86-afe7-b2fa8824a5d8" data-result="rendered">

**Wire**Weight and

**Length**Calculations for the

**Wire**Division. For more information please contact us at 888-843-2350.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="7a842b43-d3fa-46c9-8ed3-a599d8e45811" data-result="rendered">

## nt

**wire**

**length**of a single round

**wire**of common conducting materials using the

**formula**below.

**Wire**

**Length**= ( VD x 1000) / (LC x 2 x R) Where: VD = Voltage Drop LC = Load Current R = Resistance. The resistance is then matched to the corresponding

**wire**gauge value as per the American

**Wire**Gauge standard (AWG).. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="c8cc1969-d820-49c0-bd97-4a16409af920" data-result="rendered">

**wire**to gauge #2 (33.6 mm 2) the maximum

**length**is limited to approximately 32 m. Example - Calculate Maximum

**Wire**

**Length**. The electrical resistance in a copper conductor with cross sectional area 6 mm 2 is 2.9 10-3 ohm/m. This is close to

**wire**gauge 9.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="1ff11ba8-c3f2-4e9d-852a-b3026eac37c0" data-result="rendered">

**= AMPS x FEET ÷ (% VOLT DROP x VOLTAGE)**Amps = Watts divided by volts. Feet = One-way

**wire**.... " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="8156870e-b97f-4442-8a03-5720a69ae24a" data-result="rendered">

## sp

**Formula**used is, Cable size= (Fault current (in kA)*Fault clearing time)/K where, K-constant depending on the conductor and insulation used. K=90 (for Al cables), K=140 (for Cu cables) Step 2 is normally done for HT cables. For LT, if the circuit breaker used is ACB, then this step is done. For MCCB, this step is ignored.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="5748a623-6b96-497b-9496-3f36b505bb8e" data-result="rendered">

**wire**

**length**of a single round

**wire**of common conducting materials using the

**formula**below.

**Wire**

**Length**= ( VD x 1000) / (LC x 2 x R) Where: VD = Voltage Drop LC = Load Current R = Resistance. The resistance is then matched to the corresponding

**wire**gauge value as per the American

**Wire**Gauge standard (AWG).. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="87ceaf71-6960-4ef6-b52c-421637c6f58e" data-result="rendered">

## ah

**wire**is used \ ( = \)

**length of wire**in circle \ (+\)

**wire**used in \ (5\) diameters

**Length of wire**\ ( = \) Circumference

**of**a circle \ ( = 2\pi r\) \ ( = 2 \times \frac { {22}} {7} \times \frac { {35}} {2}\) \ ( = 22 \times 5 = 110\; {\rm {mm}}\) The silver

**wire**used in \ (5\) diameters \ ( = 5 \times \) diameter

**of**the circle. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="48228821-4764-4930-8058-fa20661df210" data-result="rendered">

**of**the entire

**wire**whose

**length**you wish to calculate. 3. By dividing the resistance value for the entire

**wire**by the resistance value for the 1 m

**length**, you can estimate the overall

**length of**the

**wire**(in meters). To Ensure Accurate Measurement. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="413ab001-2848-41cf-92f1-81742d4537a6" data-result="rendered">

**Length of wire formula**physics with detailed solutions. Exercise 1 : When applying a voltage of 12V to the ends of a coil

**of wire**, the current through it has a magnitude of 0.6A. Calculate the

**length**of the

**wire**used to wrap that

**wire**. Given that this type of conductor has a

**length**of 8m, the resistance is 4Ω.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="87e860e9-7c81-4e1d-9b5f-e4519a9b4c4b" data-result="rendered">

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="812bb8a5-f37f-482f-b0f7-8b14d7f70bfb" data-result="rendered">

**wire**to gauge #2 (33.6 mm 2) the maximum

**length**is limited to approximately 32 m. Example - Calculate Maximum

**Wire**

**Length**. The electrical resistance in a copper conductor with cross sectional area 6 mm 2 is 2.9 10-3 ohm/m. This is close to

**wire**gauge 9.. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="b7a17191-3740-44fa-86f8-f35a04f41162" data-result="rendered">

## xr

**Roll Length Calculator**; Contact Us. Corporate Headquarters (508) 885-8200 FAX (508) 885-8400. Troubleshooting & Support; Locations; Careers; Follow us. Sign up for .... " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="795852a5-3f5e-4438-8a31-ae8e08b1b37e" data-result="rendered">

## ke

**'wires'**are 0.25 and it does not matter whether we mean 1m and 0.25m or 1ft and 0.25ft or 1dm and 0.25dm or 1 perch and 0.25 perch, etc. so long as the units are the same. LaTeX Guide | BBcode Guide. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="7ce0547e-f110-4d49-9bed-3ec844462c17" data-result="rendered">

**wire**is used \ ( = \)

**length of wire**in circle \ (+\)

**wire**used in \ (5\) diameters

**Length of wire**\ ( = \) Circumference

**of**a circle \ ( = 2\pi r\) \ ( = 2 \times \frac { {22}} {7} \times \frac { {35}} {2}\) \ ( = 22 \times 5 = 110\; {\rm {mm}}\) The silver

**wire**used in \ (5\) diameters \ ( = 5 \times \) diameter

**of**the circle. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="ce5aaf03-920a-4594-b83b-ac3d11a8aab1" data-result="rendered">

**= AMPS x FEET ÷ (% VOLT DROP x VOLTAGE)**Amps = Watts divided by volts. Feet = One-way

**wire**.... Now, removing the sign of proportionality, we get the following resistance per unit

**length**

**formula**: R = ⍴ L/A .. (8) Or, ⍴ = RA/L Here, ⍴ is called the proportionality constant or the resistivity or the specific resistance of the material conductor. It is measured in Ohm-m. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="bcc808fb-9b5c-4e71-aa08-6c1869837562" data-result="rendered">

## fx

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="32109afe-0442-429e-9956-2b3b26fabf42" data-result="rendered">

## cq

### tc

D D = diameter of the **wire** in cm L L = **length** **of** the **wire** cm μ μ = permeability Note: The equation above is from "Inductance Calculations" by F. W. Grover Applications A **wire** can be found in any circuit, and thus, it is important to know how much inductance it is contributing.

### dp

Add 0.025" for a bare, tinned, or silver-plated copper shield **of **#36 gauge **wire**; e.g., 6 conductors **of **24 gauge, 19/36 stranded, Type E **wire **with overall shield - 2 x 0.010" (wall) = 0.020" + 0.025" (conductor O.D.) = 0.045" (finished **wire**). Taking 0.045" (finished **wire**) x 3 (Factor for 6 conductors) = 0.135".. The area of the cross section of **wire** is = Or it can be A = 3.14 × (3×10-4)2 Also, A = 28.26 × 10-8 m2 = 2.826 × 10-9 m2 It is already known that = Or, = = 25 × 2.826 × 10-9Ωm = 70.65 × 10-9Ωm Finally, = 7.065 × 10-8Ωm.

## qd

(1) into this relationship and calculate the diameter of the copper **wire** to arrive at a diameter of 0.009062 meters. d = d = (8.212395*10-5)0.5 d = 0.009062 m Now that we have the solution values, we will convert them and express our final answer using the standard units. A = 0.0000645 m2 = 64.5 mm2 d = 0.009062 m = 9.062 mm. Oct 17, 2013 · A piece of wire stretched such that its length increases and its radius decreases will tend to have its resistance increase. The formula for this is: R = ρL/A where ρ = resistivity of the material....

## ne

### fd

Cable power loss P (loss-kW) in kilowatts is equal to 1000 times of the length of the conductor l (M), the square of current I (A) in amps, the resistivity of the conductor ρ (Ω-m) in ohm-meter divided by the cross-section A (sqmm) of the conductor in (sqmm). The cable power loss calculation formula can be written as,. Web. Web. **1 Δ V = R 1000 1000 l** I where Δ V is the voltage drop, R 1000 is the resistance per 1000 feet, l is the length in feet and I is the current. There are four variables. You can find any one of them if you have the other three. You only have two variables, Δ V and R 1000 so you can't solve for l or I..

## ea

One could approximate the total **wire** **length** by taking the circumference of a single turn and multiplying it by n, the number of turns. This value will be less than the actual value because the pitch adds additional **length**. Maybe a more accurate value will be given by: **wire** **length** = n (circumference of single turn) + (n-1)p.

**Wire** **length**: L = S⋅R ρ L = S ⋅ R ρ Users of this calculator also used Calculator of reactive power from voltage and current The reactive power calculator in AC circuits will help you easily calculate reactive power, voltage and current.

Web.

FIND TOTAL **LENGTH** (ft) = CALCULATIONS FOR ROLLED ROUND CORNER RECTANGULAR **WIRE**. Breaking Force (lbs) = Thickness (inches) = ... Mount Joy **Wire** Corporation | 1000 East ....

Web.

## sa

Using Gauss's law, you should have found that the field strength (radial) at distance r from the central axis of a long straight **wire** **of** **length** ℓ and radius r 1 carrying charge Q is of magnitude. E = Q 4 π ϵ 0 ℓ r. So the pd between the surface of the **wire** (**of** radius r 1) and a surrounding co-axial conducting surface of radius r 2 is. V.

Web.

Leg C (the hypothenuse) is the unknown **guy wire** **length** that we are looking for. The "right triangle" is formed by the angle at the base of the tower or mast forming a 90 degree angle to the earth AND the guy point away from the installation. Here is the **formula**: Said another way... C squared = A squared plus B squared..

## jw

By increasing the size of the **wire** to gauge #2 (33.6 mm 2) the maximum **length** is limited to approximately 32 m. Example - Calculate Maximum **Wire** **Length**. The electrical resistance in a copper conductor with cross sectional area 6 mm 2 is 2.9 10-3 ohm/m. This is close to **wire** gauge 9..

Web.

Web.

## fs

Any calculations begin with a **formula**. The basic **formula** for calculating the resistance of a conductor is: R = (ρ * l) / S. Where R is the resistance in Ohms, ρ is the resistivity, l is the **length** in m, S is the cross-sectional area of the **wire** in mm 2.. This **formula** is suitable for calculating the resistance of a **wire** over its cross section and **length**.

**length of**the

**wire**back and forth can be calculated with Ohm's law U = R L I (2) where R = electrical resistance (ohm/m) L =

**length of wire**(m) (2) rearranged for L L = U / (R I) (2b) (2b) with values L = (12 V) 0.02 / [ (2.9 10-3 ohm/m) (10 amps)] = 8.3 m. " data-widget-price="{"amountWas":"2499.99","currency":"USD","amount":"1796"}" data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="9359c038-eca0-4ae9-9248-c4476bcf383c" data-result="rendered">

**wire**

**length**of a single round

**wire**of common conducting materials using the

**formula**below.

**Wire**

**Length**= ( VD x 1000) / (LC x 2 x R) Where: VD = Voltage Drop LC = Load Current R = Resistance. The resistance is then matched to the corresponding

**wire**gauge value as per the American

**Wire**Gauge standard (AWG).. " data-widget-price="{"amountWas":"949.99","amount":"649.99","currency":"USD"}" data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="b7de3258-cb26-462f-b9e0-d611bb6ca5d1" data-result="rendered">

**wire length calculator**it is easy to find the

**length**

**of wire**on a spool or in a drum.

**Wire**diameter [mm] Spezific weigth [g/cm³]. " data-widget-price="{"amountWas":"249","amount":"189.99","currency":"USD"}" data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="b6bb85b3-f9db-4850-b2e4-4e2db5a4eebe" data-result="rendered">

**D = Density (pounds / in ³) M = Mass (pounds) G = Gauge (inches) W = Width (inches) R = Radius (inches)**L

**= Length (feet)**P = 3.14159 ESM is accredited / approved by Elgiloy Specialty Metals.

**Length**is calculated to the top of the drum flange minus selected freeboard (i.e. clearance) . If "Full drum" is selected under Freeboard options then the

**length**is calculated to the top of the flange without any freeboard, The (3) dead (anchoring) wraps are included in all outputs. " data-widget-type="deal" data-render-type="editorial" data-viewports="tablet" data-widget-id="b139e0b9-1925-44ca-928d-7fc01c88b534" data-result="rendered">